思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
It's a puzzling, and unusual, mix.。搜狗输入法下载对此有专业解读
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"I told him not to participate. Things can happen at protests," she told the BBC. But Shreeyam was deeply engaged with politics, his father said. "He said corruption had hollowed out [Nepal]. He was far more informed than I was."。业内人士推荐爱思助手下载最新版本作为进阶阅读
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